A + B

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 8539 Accepted Submission(s): 4810

Problem Description

读入两个小于100的正整数A和B,计算A+B.

需要注意的是:A和B的每一位数字由对应的英文单词给出.

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出.

Output

对每个测试用例输出1行,即A+B的值.

Sample Input

one + two = three four + five six = zero seven + eight nine = zero + zero =

Sample Output

3 90 96

View Code

1 #include 
        
          2 #include 
         
           3 #include 
           4 #include 
           
             5 using namespace std; 6  7 map 
            
              f; 8  9 int main() {10     int sum1, sum;11     string str;12     f["one"]=1;13     f["zero"]= 0;14     f["two"]= 2;15     f["three"] = 3;16     f["four"]=4;17     f["five"]=5;18     f["six"]=6;19     f["seven"]=7;20     f["eight"]=8;21     f["nine"]=9;22     while(1)23     {24         sum=0;25         while(1)26         {27             cin>>str;28             if(str=="+")29             break;30             sum=sum*10+f[str];31         }32         sum1=0;33         while(1)34         {35             cin>>str;36             if(str=="=")37             break;38             sum1=sum1*10+f[str];39         }40         41         if(sum==0 && sum1 ==0)42         break;43         cout <
             
              << endl;44 }45 return 0;46 }